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20=2.5x+x^2
We move all terms to the left:
20-(2.5x+x^2)=0
We get rid of parentheses
-x^2-2.5x+20=0
We add all the numbers together, and all the variables
-1x^2-2.5x+20=0
a = -1; b = -2.5; c = +20;
Δ = b2-4ac
Δ = -2.52-4·(-1)·20
Δ = 86.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2.5)-\sqrt{86.25}}{2*-1}=\frac{2.5-\sqrt{86.25}}{-2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2.5)+\sqrt{86.25}}{2*-1}=\frac{2.5+\sqrt{86.25}}{-2} $
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